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Answered by hemant2807
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Answered by spacelover123
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Question

Solve → [(\frac{1}{4})^{-3} - (\frac{2}{3})^{-3}]\div (\frac{4}{7})^{-2}

\rule{300}{1}

Answer

For this question we must apply laws of exponents.

We'll apply this law of exponent first ⇒ a^{-m}=\frac{1}{a^{m}}

[(\frac{1}{4})^{-3} - (\frac{2}{3})^{-3}]\div (\frac{4}{7})^{-2}

[(4)^{3} - (\frac{3}{2})^{3}]\div (\frac{7}{4})^{2}

Now we will find the actual value and remove the exponent.

[64 - \frac{27}{8}]\div \frac{49}{16}

We shall do the brackets first according to BODMAS.

[\frac{64\times 8 }{1 \times 8 }  - \frac{27}{8}]\div \frac{49}{16}

[\frac{512 }{8 }  - \frac{27}{8}]\div \frac{49}{16}

\frac{485}{8}  \div \frac{49}{16}

Since this is division of fraction we must find reciprocal of second number and multiply.

\frac{485}{8}  \times \frac{16}{49}

\frac{485}{8\div 8}  \times \frac{16\div 8 }{49}

\frac{485}{1}  \times \frac{ 2 }{49}

\frac{970}{49}

\bf \therefore [(\frac{1}{4})^{-3} - (\frac{2}{3})^{-3}]\div (\frac{4}{7})^{-2} = \frac{970}{49}

\rule{300}{1}

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