Question

pls answer only if you are sure

Answer 1

Hey......!!! Here is ur answer.....☺️☺️☺️

Given that,

sin(x+y)/sin(x–y) = (a+b)/(a–b)...........(1)

as we know that....
sin (A+B) = sinA.cosB + cosA.sinB
& sin(A–B) = sinA.cosB – cosA.sinB

(sinx.cosy + cosx.siny)/(sinx.cosy – cosx.siny) = (a+b)/(a–b)

On comparing L.H.S. and R.H.S. in equation (1)

we got a = sinx.cosy & b = cosx.siny

then a/b = sinx.cosy/cosx.siny

a/b = (sinx/cosx).(cosx/siny)

a/b = tanx.coty

a/b = tanx/tany.........Hence Proved.

I hope it will help u......✌️✌️✌️