pls answer pls pls pls
Attachments:
Answers
Answered by
0
xy[(x+y)(1/x+1/y)]=(x+y)²
xy[(x·1/x + x · 1/y + y·1/x + y·1/y)]
xy(x/y + y/x)
xy·x/y + xy·y/x
x²+y²
(x+y)²
xy[(x·1/x + x · 1/y + y·1/x + y·1/y)]
xy(x/y + y/x)
xy·x/y + xy·y/x
x²+y²
(x+y)²
prajwalbode01:
Plz. mark my answer Brainliest if it was helpful
Answered by
0
xy{x+y}{1/x+1/y} =xy{1+x/y+1+y/x}
=xy+x^2+xy+y^2
=x^2+y^2+2xy=[x-y]^2
=x^2+y^2+2xy=x^2+y^2-2xy
=4xy
=xy+x^2+xy+y^2
=x^2+y^2+2xy=[x-y]^2
=x^2+y^2+2xy=x^2+y^2-2xy
=4xy
Similar questions