Math, asked by prathimanikesh, 1 year ago

pls answer pls pls pls

Attachments:

Answers

Answered by prajwalbode01
0
xy[(x+y)(1/x+1/y)]=(x+y)²
xy[(x·1/x + x · 1/y + y·1/x + y·1/y)]
xy(x/y + y/x)
xy·x/y + xy·y/x
x²+y²
(x+y)²

prajwalbode01: Plz. mark my answer Brainliest if it was helpful
ammuludaddy192: once verify ur answer it might be wrong
Answered by ammuludaddy192
0
xy{x+y}{1/x+1/y} =xy{1+x/y+1+y/x}
                           =xy+x^2+xy+y^2
                           =x^2+y^2+2xy=[x-y]^2
                           =x^2+y^2+2xy=x^2+y^2-2xy
                           =4xy

prajwalbode01: Verify ur ones first!
prajwalbode01: It's correct
prajwalbode01: He might have did mistake in que.
ammuludaddy192: yaaa
Similar questions