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Let a=120m b=80m c=50m
s=a+b+c/2
=120+80+50/2
=250/2
=125m
From heron's formula
Area of triangle=√s(s-a)(s-b)(s-c)
=√125*5*45*75
=√5*5*5*5*5*3*3*5*5*3
=375√15m2
Perimeter of trianglular park=250m
Space left for fencing=250-3
=247m
Cost of fencing 247m=247*20
=Rs.4940
s=a+b+c/2
=120+80+50/2
=250/2
=125m
From heron's formula
Area of triangle=√s(s-a)(s-b)(s-c)
=√125*5*45*75
=√5*5*5*5*5*3*3*5*5*3
=375√15m2
Perimeter of trianglular park=250m
Space left for fencing=250-3
=247m
Cost of fencing 247m=247*20
=Rs.4940
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