Question

pls answer properly​

Answer 1

Answer:

Ar. of ∆ = ½×b×h

NOW,

ar. ∆ ABC = ½ × BC × AO

Also,

ar. ∆ DBC = ½ × BC × OD

So,

Area of ABC/Area of DBC = AO/DO             [1/2 and equal base bc are cancelled]

✔HENCE PROVED ✔

Answer 2

Step-by-step explanation:

A (ABC)=1/2 ×BC×AL....(1)

A (DBC)=1/2 ×BC×DM....(2)

From (1) and (2),

A (ABC)/A (DBC)=AL/DM