Question

pls answer properly and don't spam or don't write wrong answer pls :)​

Answer 1

Answer:

${ \dfrac{2}{3}}^{3x - 3} \times { \dfrac{2}{3}}^{ - 5} = {\dfrac{2}{3}}^{10} \\ { \dfrac{2}{3}}^{3x - 3 + ( - 5)} = { \dfrac{2}{3}}^{10} \\ 3x - 8 = 10 \\ 3x = 18 \\ x = \dfrac{ \cancel{\: 18 \: }^{ \: \: 6} }{ \cancel3} \\ \boxed{ \blue{ \boxed{\bold{ \orange{x = 6}}}}}$

$\begin{gathered}\boxed{\begin{minipage}{5 cm}\bf{\dag}\:\:\underline{\text{Law of Exponents :}}\\\\\bigstar\:\:\sf\dfrac{a^m}{a^n} = a^{m - n}\\\\\bigstar\:\:\sf{(a^m)^n = a^{mn}}\\\\\bigstar\:\:\sf(a^m)(a^n) = a^{m + n}\\\\\bigstar\:\:\sf\dfrac{1}{a^n} = a^{-n}\\\\\bigstar\:\:\sf\sqrt[\sf n]{\sf a} = (a)^{\dfrac{1}{n}}\end{minipage}}\end{gathered}$