Pls ANSWER Q 45
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Anonymous:
the answer is c.
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The required answer is option c.
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As the fish sees through the diameter of the circle hence the radius be r and the depth from the top to the fish be h. The fish sees through an angle of C.
So, tanC = r/h.
So, r= h*tanC.
So, r=h*sinC/cosC.
So, r = hsinC/√(1-sin^2C).
Now, we know that the value of sinC will be 1/n, where n is the refractive index of water.
So, r = h*1/n / √(1 - 1/n^2).
So, r = h / √(n^2 - 1).
So, the diameter of the circle will be twice the radius.
Diameter = 2h/√(n^2 - 1).
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