pls answer question 6
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Your question is what should be subtracting from (-x²+y²+6xy+20) so that we get (3x²+4y²-5xy+2) ..
(-x²+y²+6xy+20) - (3x²+4y²-5xy+2)
=> -x²+y²+6xy+20 -3x²-4y²+5xy+2
=> -x²-3x²+y²-4y²+6xy+5xy+20+2
=> -4x²-3y²+11xy+22
so, if we subtract (-4x²-3y²+11xy+22) from (-x²+y²+6xy+20) we get (3x²+4y²-5xy+2) .....
Hope it helps you ....
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