Math, asked by shauryamohanty990, 10 months ago

pls answer question 6​

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Answered by RvChaudharY50
11

Your question is what should be subtracting from (-x²++6xy+20) so that we get (3x²+4y²-5xy+2) ..

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(-x²+y²+6xy+20) - (3x²+4y²-5xy+2)

=> -x²++6xy+20 -3x²-4y²+5xy+2

=> -x²-3x²+-4y²+6xy+5xy+20+2

=> -4x²-3y²+11xy+22

so, if we subtract (-4x²-3y²+11xy+22) from (-x²+y²+6xy+20) we get (3x²+4y²-5xy+2) .....

Hope it helps you ....

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