pls answer question no 26
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A.P: 103, 110, 117, ...., 999
a = 103 d = 7
n be the number of terms
an = 999
103 + (n - 1)7 = 999
103 + 7n - 7 = 999
7n + 96 = 999
7n = 903
n = 129
Middle term = (n+1/2)th term = 65th term = a + 64d = 103 + 64 x 7 = 551
Sn = n/2 [2a + (n - 1)d]
S64= 64/2 [2 x 103 + 63 x 7] = 20704
S129 = 129/2 [2 x 103 + 128 x 7] = 71079
S129 - (S64 + 551) = 71079 - (20704 + 551) = 49824
hope this helps , plzzz mark as brainliest.
a = 103 d = 7
n be the number of terms
an = 999
103 + (n - 1)7 = 999
103 + 7n - 7 = 999
7n + 96 = 999
7n = 903
n = 129
Middle term = (n+1/2)th term = 65th term = a + 64d = 103 + 64 x 7 = 551
Sn = n/2 [2a + (n - 1)d]
S64= 64/2 [2 x 103 + 63 x 7] = 20704
S129 = 129/2 [2 x 103 + 128 x 7] = 71079
S129 - (S64 + 551) = 71079 - (20704 + 551) = 49824
hope this helps , plzzz mark as brainliest.
jashan911:
thanx thanx very much
can u pls tell how u make the series
i have understood how u make the series
thanx once again for solving question
hey that is not a problem , if u have any more doubts then you are welcome to ask me.
thanks for marking the brainliest
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