Math, asked by jashan911, 1 year ago

pls answer question no 26

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Answered by Aishwarya00001

A.P: 103, 110, 117, ...., 999

a = 103 d = 7

n be the number of terms

an = 999

103 + (n - 1)7 = 999

103 + 7n - 7 = 999

7n + 96 = 999

7n = 903

n = 129

Middle term = (n+1/2)th term = 65th term = a + 64d = 103 + 64 x 7 = 551

Sn = n/2 [2a + (n - 1)d]

S64= 64/2 [2 x 103 + 63 x 7] = 20704

S129 = 129/2 [2 x 103 + 128 x 7] = 71079

S129 - (S64 + 551) = 71079 - (20704 + 551) = 49824

hope this helps , plzzz mark as brainliest.

jashan911: thanx thanx very much

jashan911: can u pls tell how u make the series

jashan911: i have understood how u make the series

jashan911: thanx once again for solving question

Aishwarya00001: hey that is not a problem , if u have any more doubts then you are welcome to ask me.

Aishwarya00001: thanks for marking the brainliest

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