Pls answer question no. 5...
Correct answer would be marked brainliest....
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Rashi937:
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Answered by
2
dv/dt =1-2v
1/(1-2v)dv =dt
Now integrated both sides
1/2*-ln(1-2v) =t
1-2v =e^-2t
V =1/2*(1-e^-2t)
So option D is the right answer
1/(1-2v)dv =dt
Now integrated both sides
1/2*-ln(1-2v) =t
1-2v =e^-2t
V =1/2*(1-e^-2t)
So option D is the right answer
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Answered by
1
the motion of a body falling from rest in a medium is given by equation 
![\frac{dv}{dt}=1-2v\\\\dv=(1-2v)dt\\\\\\\int\limits^v_0{\frac{1}{1-2v}}\,dv=\int\limits^t_0dt\\\\\\\left[\frac{-1}{2}ln|1-2v|\right]^v_0=t\\\\1-2v=e^{-2t}\\\\v=\frac{1}{2}(1-e^{-2t})](https://tex.z-dn.net/?f=%5Cfrac%7Bdv%7D%7Bdt%7D%3D1-2v%5C%5C%5C%5Cdv%3D%281-2v%29dt%5C%5C%5C%5C%5C%5C%5Cint%5Climits%5Ev_0%7B%5Cfrac%7B1%7D%7B1-2v%7D%7D%5C%2Cdv%3D%5Cint%5Climits%5Et_0dt%5C%5C%5C%5C%5C%5C%5Cleft%5B%5Cfrac%7B-1%7D%7B2%7Dln%7C1-2v%7C%5Cright%5D%5Ev_0%3Dt%5C%5C%5C%5C1-2v%3De%5E%7B-2t%7D%5C%5C%5C%5Cv%3D%5Cfrac%7B1%7D%7B2%7D%281-e%5E%7B-2t%7D%29 "\frac{dv}{dt}=1-2v\\\\dv=(1-2v)dt\\\\\\\int\limits^v_0{\frac{1}{1-2v}}\,dv=\int\limits^t_0dt\\\\\\\left[\frac{-1}{2}ln|1-2v|\right]^v_0=t\\\\1-2v=e^{-2t}\\\\v=\frac{1}{2}(1-e^{-2t})")
hence, option (4) is correct.
hence, option (4) is correct.
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