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bro the photo is not clear send a clear photo
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Here is your proof.
Step-by-step explanation:
In quadrilateral ACBD,
There are two triangles, Δ ACB and Δ ADB.
In Δ ACB and Δ ADB,
AC = AD (Given)
∠DAB = ∠CAB (Given)
AB = AB (Common)
∴ Δ ACB ≅ Δ ADB (SAS Congruence rule)
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