Question

Pls answer quick!
Quickest will be brainliest and will get 20 points!!

Answer 1

Answer:

a=-4, b=13, remainder=-33

Step-by-step explanation:

Given:

x^4-2x^3+3x^2-ax+b

1)  when divided by x+1, the remainder is 5

• x^4-2x^3+3x^2-ax+b-5=0 if x=-1
• 1-2-3+a+b-5=0
• a+b-9=0
• a+b=9        ----------(1)

2)  when divided by x-1, the remainder is 19

• x^4-2x^3+3x^2-ax+b-19=0 if x=1
• 1-2+3-a+b-19=0
• -a+b-17=0
• -a+b=17      ----------(2)

(1)+(2) => -a+b+a+b=26 => 2b=26 => b=13 => a=-4

Function now with known values of a and b:

• f(x)=x^4-2x^3+3x^2+4x+13

Now, let's find the remainder when dividend is x-2

• x^4-2x^3+3x^2+4x+13=
• (x^2-2x^3)+(3x^2-6x)+(10x-20)-33=
• (x-2)(x^2+3x+10) - 33

As we can see the remainder is = -33

Hope it is of help

Answer 2

Answer:hope this helps you

Please keep as the brainliest

Step-by-step explanation: