Physics, asked by Intellectual88, 9 months ago

pls answer quickly ​

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Answered by GradeupYourBrainYT
1

Answer:

Given: R1=1ohm

           R2= 0.5ohm

           both are in parallel form so

Solution: Req, 1/Req=1/R1+1/R2

1/Req=1+1/0.5

1/Req= 1+2

Req=1/3 ohm

and from ohm's rule

V=i×Req

3=i×1/3

then I =9 A

energy= V×i×t

energy = 3×9×1  

energy= 27 joule

mark me as a brainalist

Answered by ravindaran
0

Answer:

a) 27j

Explanation:

R1=1ohm, R2= 0.5ohm both are in parallel form so Req, 1/Req=1/R1+1/R2, 1/Req=1+1/0.5, 1/Req= 1+2, Req=1/3 ohm , and from ohm's rule V=i×Req, 3=i×1/3, then I =9 A, energy= V×i×t , energy = 3×9×1 , energy= 27 joule

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