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Answer:
Given: R1=1ohm
R2= 0.5ohm
both are in parallel form so
Solution: Req, 1/Req=1/R1+1/R2
1/Req=1+1/0.5
1/Req= 1+2
Req=1/3 ohm
and from ohm's rule
V=i×Req
3=i×1/3
then I =9 A
energy= V×i×t
energy = 3×9×1
energy= 27 joule
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Answered by
0
Answer:
a) 27j
Explanation:
R1=1ohm, R2= 0.5ohm both are in parallel form so Req, 1/Req=1/R1+1/R2, 1/Req=1+1/0.5, 1/Req= 1+2, Req=1/3 ohm , and from ohm's rule V=i×Req, 3=i×1/3, then I =9 A, energy= V×i×t , energy = 3×9×1 , energy= 27 joule
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