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If a cell of EMF e is charged by passing current I through it from a battery, The terminal voltage of the cell is then e+v(voltage drop) that is terminal voltage is greater than its EMF.
Give reason for this?
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as far as I know terminal voltage is never greater than EMF it's equal to end when the cell is not in use and less than emf when the cell is in use ...
But as far as the question is in concern then the terminal voltage might be greater than EMF when the voltage drop is negative....
(pls correct is wrong)
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