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an edge is increased by 10 percentage find the persentage by which the surface area of the cube has increased
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Let the edge be x
SA=6x^2
Edge increased by 10%
Edge increase=10/100*x=x/10
New edge= 11x/10
New SA=6(11x/10)^2=726x^2/100
SA increase=726x^2/100-6x^2=126x^2/100
Percent increase=SA increase/Original SA*100=126x^2/100/6x^2*100=126x^2/100*6x^2*100=21%
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