pls answer really quick with law of exponents
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Answer:
a) (1-1)+3 [a^0=1] [a^1=a]
=0+3 =3
b) (-5/8)^3+7 [a^m× a^n= a^m+n]
=(-5/8)^10
c)5^8÷5^3 = 5^8-3 [a^m÷a^n= a^m-n]
=5^5
d) (2/3)^6 ÷(2/3)^6 [(a^m)^n=a^mn]
= 1
Hope it Helps!
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Answer:
sorry dude cannot answer don't know
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