Question

pls answer step by step



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Answer 1

Answer:

Given:

A bucket contains 20 1/4 litres of water

A small jug has a capacity of 3/4 litre.

To find:

How many times the small jugs of  has to be filled with water from the bucket to get it emptied?

Solution:

The quantity of water present inside the bucket =  

The capacity of each small jug =  

Let "n" represent the no. of times a small jug with a capacity of  has to be filled to empty the bucket.

Therefore, we will calculate the value of n as follows:

Thus, the small jug has to be filled 27 times with water from the bucket to get it emptied.

Answer 2

Step-by-step explanation:

i)Water the Bucket can contain = 20 1/4 litres= 81/4 litres

small jug's capacity= 3/4 litres

Taking the number of times the jug would have to filled with water from the bucket to empty it as= x

The above statements can be written in a equation form as below-

81/4= x × 3/4

81/4 / 3/4 = x

81/3= x

27 = x

Hence the number of times the jug would have to filled with water from the bucket to empty it is 27 times

ii)The water the bucket can contain remains the same so it will still be 81/4 litres

The amount of water the larger jug can carry= 9/4

Taking the number of times the larger jug would have to filled with water from the bucket to empty it as= y

The above statements can be written in a equation form as below-

81/4 = y × 9/4

81/4 / 9/4 =y

81/9= y

9= y

Hence the number of times the larger jug would have to filled with water from the bucket to empty it is 9 times

Hope it helped