Question

pls answer the 1 st question
class 10 , 11 and 12
tomorrow is my exam i need the answer for this question
first right answer will be marked brainlist ​

Answer 1

Answer:

Let assume that base of triangle and parallelogram be x cm.

Case :- 1

Base of triangle = x cm

Height of triangle, h = 12 cm

We know,

\begin{gathered}\boxed{ \rm{ \:Area_{(triangle)} = \frac{1}{2} \times Base \times Height \: }} \\ \end{gathered}

Area

(triangle)

=

2

1

×Base×Height

So, on substituting the values, we get

\begin{gathered}\rm \: \:Area_{(triangle)} = \frac{1}{2} \times x \times 12 \: \\ \end{gathered}

Area

(triangle)

=

2

1

×x×12

\begin{gathered}\rm\implies \:\rm \: \:Area_{(triangle)} = 6x \: {cm}^{2} \: \\ \end{gathered}

⟹Area

(triangle)

=6xcm

2