Question

pls answer the 11 question pls​

Answer 1

Firstly let us assume that,

→ 3x - 4y + 3 = 0 is Equation 1

→ 3x + 4y = 21 is Equation 2

• For Equation 1st

~ Firstly let us put x as 0

→ 3x - 4y + 3 = 0

→ 3(0) - 4y + 3 = 0

→ 0 - 4y + 3 = 0

→ 0 + 3 - 4y = 0

→ 3 - 4y = 0

→ -4y = 0-3

→ -4y = -3

→ 4y = 3

→ y = 3/4

→ y = 0.75

→ y ≈ 0.8

∴ (0,0.8) is coordinate here

~ Now let's put y = 0

→ 3x - 4y + 3 = 0

→ 3x - 4(0) + 3 = 0

→ 3x - 0 + 3 = 0

→ 3x + 3 = 0

→ 3x = 0 - 3

→ 3x = -3

→ x = -3/3

→ x = -1

∴ (-1,0) is coordinate here

• For Equation 2nd

~ Firstly let us put x = 0

→ 3x + 4y = 21

→ 3(0) + 4y = 21

→ 0 + 4y = 21

→ 4y = 21

→ y = 21/4

→ y = 5.25

→ y ≈ 5.3

∴ (0,5.3) is coordinate here

~ Now let's put y = 0

→ 3x + 4y = 21

→ 3x + 4(0) = 21

→ 3x + 0 = 21

→ 3x = 21

→ x = 21/3

→ x = 7

∴ (7,0) is coordinate here

• They intersect at (3,3) $\:$

Answer 2

$\huge\color{blue}\boxed{\colorbox{lightgreen}{♧Ânswer♧}}\bigstar$

Firstly let us assume that,

→ 3x - 4y + 3 = 0 is Equation 1

→ 3x + 4y = 21 is Equation 2

For Equation 1st

~ Firstly let us put x as 0

→ 3x - 4y + 3 = 0

→ 3(0) - 4y + 3 = 0

→ 0 - 4y + 3 = 0

→ 0 + 3 - 4y = 0

→ 3 - 4y = 0

→ -4y = 0-3

→ -4y = -3

→ 4y = 3

→ y = 3/4

→ y = 0.75

→ y ≈ 0.8

∴ (0,0.8) is coordinate here

~ Now let's put y = 0

→ 3x - 4y + 3 = 0

→ 3x - 4(0) + 3 = 0

→ 3x - 0 + 3 = 0

→ 3x + 3 = 0

→ 3x = 0 - 3

→ 3x = -3

→ x = -3/3

→ x = -1

∴ (-1,0) is coordinate here

For Equation 2nd

~ Firstly let us put x = 0

→ 3x + 4y = 21

→ 3(0) + 4y = 21

→ 0 + 4y = 21

→ 4y = 21

→ y = 21/4

→ y = 5.25

→ y ≈ 5.3

∴ (0,5.3) is coordinate here

~ Now let's put y = 0

→ 3x + 4y = 21

→ 3x + 4(0) = 21

→ 3x + 0 = 21

→ 3x = 21

→ x = 21/3

→ x = 7

∴ (7,0) is coordinate here

They intersect at (3,3) 

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