Question

Pls answer the 22nd question.
The first one to answer will be marked as the brainliest

Answer 1

Hey mate ☺

In ∆ABC,

$\tan(60) = \frac{ab}{bc} \\ \sqrt{3 } = \frac{150}{x} \\ x = \frac{150}{ \sqrt{3} } \\ x = \frac{150 \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } \\x = \frac{150 \sqrt{3} }{3} \\ x = 50 \sqrt{3} \\bc = 50 \sqrt{3}$

let time in seconds,

2minutes=2×60=120seconds

In ∆ABD,

$\tan(45) = \frac{ab}{bd} \\ 1 = \frac{150}{120s + x} \\ 120s + 50 \sqrt{3} = 150 \\ 120s = 150 - 50 \sqrt{3} \\ 120s = 50(3 - \sqrt{3} ) \\ 120s = 50(3 - 1.73) \\ 120s = 50(1.268) \\ 120s = 63.4 \\ s = \frac{63.4}{120} \\ s = \frac{317}{600}$

$in \: hours \\ s = \frac{317}{600} \times3600 \\ s = 317 \times 6 \\ s = 1902m {hr}^{ - 1}$

Hope it helps you ☺✌✌