Math, asked by Sanchi1214, 1 year ago

Pls answer the 27 question

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Answered by s55555a
1
areaof quadrilateral=DB+1/2(M+L)

Sanchi1214: what is M+L
s55555a: hieghts of the quadrilateral
Sanchi1214: OK
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s55555a: ls
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Answered by vamsi128
1
area =
(one \: diagonal \:  \times (sum \: of \: perpendicular \: drawn \: to \: this \: diagonal \: ) \:  )1 \div 2
I.e 1/2 ×(AL + CM ) × BD
1/2 ×( 16.8+13.2) × 64 = 960
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