Question

PLS ANSWER THE 30TH QUESTION
(URGENT)

Answer 1

$bf || cf$
<CBF = <BCE
<CBF=1/2 <BCZ
<BCZ=1/2 <YBC

AS CBF =BCZ
$\frac{1}{2} \times < zcb = \frac{1}{2} \times < ybc \\ < zcb = < ybc \\ so \: xy || uz \\ because < zcb = < ybc \: alternateangle \:$

Answer 2

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