pls answer the 4th question
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Hardik4Noone:
hey x=84 y=21 z=48
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Answered by
0
angle COA +ANGLE COB= 180
84+2Z=180
Z=180÷2-84
Z=48
ANGLE BOD=ANGLE COA (vertically opposite. angle)
x=84
angle AOE+EOD+DOB=180
75+Y+84=180
159+Y=180
Y=180-159
Y= 21
X=84
Z=48
Y=21
84+2Z=180
Z=180÷2-84
Z=48
ANGLE BOD=ANGLE COA (vertically opposite. angle)
x=84
angle AOE+EOD+DOB=180
75+Y+84=180
159+Y=180
Y=180-159
Y= 21
X=84
Z=48
Y=21
Answered by
3
HEYA MATE,
Here is your answer
NOTE - '/' refers to angle
______________________________
BRIEF ANSWER: X = 84° ;
Y = 21° ;
2Z =96° ; Z = 48° ;
______________________________
EXPLAINED ANSWER:
/AOC = /X = 84° [ Vertically opposite /'s ]
=============================
{We know that, /AOD = /AOE + /Y } ____(1)
Now, /AOD + /AOC = 180°
{ When a ray stands on a line, it forms supplementary /'s }
=> /AOD + 84° = 180°
=> /AOD = 96° _____(2)
=> /AOE +/Y = 96° { From (1) }
=> 75° + Y = 96°
=> Y = 21°
Now, /AOD = /2Z { VERTICALLY OPPOSITE/'s }
We know that, /AOD = 96°
=> 2Z = 96°
=> Z =
=> Z = 48°
_______________________________
Hope this helps ❤️❤️❤️❤️❤️
Here is your answer
NOTE - '/' refers to angle
______________________________
BRIEF ANSWER: X = 84° ;
Y = 21° ;
2Z =96° ; Z = 48° ;
______________________________
EXPLAINED ANSWER:
/AOC = /X = 84° [ Vertically opposite /'s ]
=============================
{We know that, /AOD = /AOE + /Y } ____(1)
Now, /AOD + /AOC = 180°
{ When a ray stands on a line, it forms supplementary /'s }
=> /AOD + 84° = 180°
=> /AOD = 96° _____(2)
=> /AOE +/Y = 96° { From (1) }
=> 75° + Y = 96°
=> Y = 21°
Now, /AOD = /2Z { VERTICALLY OPPOSITE/'s }
We know that, /AOD = 96°
=> 2Z = 96°
=> Z =
=> Z = 48°
_______________________________
Hope this helps ❤️❤️❤️❤️❤️
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