Question

pls answer the 5th one​

Answer 1

Hi mate

The detailed answer to ur problem is...
In a non-leap year there will be 52 Sundays and 1day will be left. This 1 day can be Sunday, Monday, Tuesday, Wednesday, Thursday,friday,Saturday, Sunday. Of these total 7 outcomes, the favourable outcomes are 1. Hence the probability of getting 53 sundays = 1 / 7.

Mark as brainliest.........

Answer 2

Answer:1/7

Step-by-step explanation:

A non leap year has 365 days.

There are 52 weeks each having 7 days.

This amounts to 52 x 7 = 364 days.

The remaining 1 day can be any day among Monday, Tuesday,..., Sunday.

Hence the required probability is 1/7.