Question

pls. answer the 6 and 7 question fast

Answer 1

BP//DQ andPQ is a transversal,
so,BPQ+DQP=180°
since,OP and OQ bisects so,
BPQ/2+DQP/2=180/2
OPQ+OQP=90
POQ+(OPQ+OQP)=180
POQ+90=180
OPQ=90

ABC+XBC=180(linear pair),
BAZ+BAC=180
BCA+ACY=180
(ABC+BAC+BCA)+XBC+BAZ+ACY=540
180+XBC+BAZ+ACY=540
XBC+BAZ+ACY=360

Answer 2

<BPQ = 90 degrees , and is bisected so <QPO = 45, since both <QPO an <PQO are 45 degrees, <O = 90 degrees [ 180 - (45 + 45) ]