Pls answer the 75and76
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Answer:
75.(5y^2+4)(2y^2-3)
76. 2(9z-4)(9z+4)
Step-by-step explanation:
By middle term splitting
75. 10y^4-7y^2-12
=10y^4+(-15+8)y^2-12
=10y^4-15y^2+8y^2-12
=5y^2(2y^2-3)+4(2y^2-3)
Taking Common 2y^2-3
=(5y^2+4)(2y^2-3)
By using identity (a^2)-(b^2)=(a+b)(a-b)
76.162z^2-32
=2(81z^2-16)
=2[{9z}^2-{4}^2]
=2(9z-4)(9z+4)
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