Question

Pls answer the Above Question​

Answer 1

Answer:

THE SUM OF ALL THE ANGLES OF A QUADRILATERAL IS 360°.

.°. THE SUM OF OPPOSITE ANGLES OF A QUADRILATERAL WILL BE 180°.

LET ANGLE P BE 'A' AND ANGLE R BE 'B'.

.°. A+B=180°

AND GIVEN A - B = 50°

=> A = B+50°

CONSIDERING A+B=180° AS A=90° AND B=90° ;

=> A = 90+50

=> A = 140°

Step-by-step explanation:

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Answer 2

Angle P

140°

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