pls answer the above question
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Step-by-step explanation:
16^x + 36^x = 81^x
[ (16^x) / (81^x) ] + [ (36^x) / (81^x) ] = 1
[4/9]^2x + [4/9]^x - 1 = 0
Let, y = (4/9)^x
Solve the quadratic in y, then substitute
x = ln (y) / ln (4/9)
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