Question

pls answer the above question. ​

Answer 1

Step-by-step explanation:

x^2 - 2x + 1 =0

x^2 -x -x + 1 =0

x(x - 1) -1(x-1) =0

(x - 1)(x - 1) = 0

x - 1 =0

x = 1

OR

x^2 - 2x + 1 =0

[(a - b)^2 = a^2 + b^2 -2ab]

By comparing

(x - 1)^2 =0

x - 1 =0

x = 1

Answer 2

hopefully its helped u dear :)