Question

Pls answer the above two questions. The first person who answers I will make that person a brainlist.

Answer 1

1)
$\frac{ {7}^{48} - {7}^{47} - {7}^{46} }{41} = {7}^{x} \\ {7}^{46} ( \frac{ {7}^{2} - 7 - 1)}{41} = {7}^{x} \\ {7}^{46} ( \frac{41}{41} ) = {7}^{x} \\ so \: by \: compairing \\ \\ x = 46$

2)
$4 \sqrt{3x + 1} = 2 \\ \sqrt{3x + 1} = \frac{1}{2} \\ on \: squaring \: both \: sides \\ \\ 3x + 1 = \frac{1}{4} \\ 12x + 4 = 1 \\ 12x = - 3 \\ x = - \frac{1}{4}$

Hope it will help you.

Answer 2

1.

[7^48 - 7^47 - 7^46]/41 = 7^x

⇒ 7^46 * (7^2 -7^1 -1) / 41 = 7^x

⇒ 7^46 * (49-7-1)/41 = 7^x

⇒ 7^46 * 41/41 = 7^x

⇒7^x=7^46

Since bases are equal powers are also equal

So, x=46

2.

4√(3x+1) = 2

⇒ √(3x+1) = 2/4 = 1/2

squaring on both sides

⇒ [√(3x+1) ]² = 1/2²

⇒ 3x+1 = 1/4

⇒ 3x+1 = 1/4

⇒3x = -3/4

⇒ x = -1/4