Math, asked by Anonymous, 4 months ago

pls answer the attached Q..

☹️☹️..

Attachments:

subhsamavartj: pla mark as brainliest

subhsamavartj: pla

subhsamavartj: plz it took a lot of time

Anonymous: yes , sure I will

subhsamavartj: but you havent marked

subhsamavartj: pls mark

Anonymous: I have not got the option to mark

Anonymous: i can mark only after the anyone else gives the answer

Answers

Answered by kuhu005

Step-by-step explanation:

Multiplyboth sides by (1-cosA)(1-cosB)(1-cosC).

It makes both the sides (1-cosA)²(1-cosB)²(1-cosC)²=sin²Asin²Bsin²C

So ,

(1-cosA)(1-cosB)(1-cosC)-sinAsinBsinC=0

(1-cosA)(1-cosB)(1-cosC)+sinAsinBsinC=0.

Hence proved

hope it will be helpful to you

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