Question

Pls answer the attached question.

Answer 1

Question :

A bomb of mass 20kg is moving with a velocity of 10 m/s on a straight path and suddenly explodes into two fragments. One moves in the same direction with velocity of 40 m/s and other in opposite with velocity of 20 m/s. Find the magnitude of the masses.

Solution :

Since no external force acts on the system, linear momentum is conserved.

• We know that momentum is measured as the product of mass and velocity.

Mathematically, p = m v

Let mass of first fragment be m kg$.$

∴ Mass of another fragment will be (20 - m) kg.

➙ P = P₁ + P₂

➙ Mu = m v₁ + (20 - m) v₂

➙ 20 × 10 = m (40) + (20 - m) (-20)

➙ 200 = 40m - 400 + 20m

➙ 600 = 60m

➙ m = 600/60

➙ m = 10 kg

∴ Mass of the first fragment = 10kg

♦ Mass of the another fragment :

➠ m' = (20 - m)

➠ m' = 20 - 10

➠ m' = 10 kg