pls answer the attachment and explai
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Step-by-step explanation:
8x^3-y^3-12x^2y+6xy^2
= (2x)^3-(y)^3-3(2x)^2(y)+3(2x)(y^2)
Therefore, a^3-b^3+3a^2b+3ab^2=(a-b)^3
a=2x, b=y
(2x-y)^3
Do all sums like this
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Q.x³ -3x²-10x+24
= x³ + (1)³ - 3(x+1)(x * 1)
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