Question

pls answer the below

Answer 1

Answer:

(1−2

0

x)(1−2

1

x)(1−2

2

x).....(1−2

15

x)

Maximum power of x=16

Power of x

15

=1+2+3+...+15=120

We can tell the coefficient of x

15

=(−1)(2

120

+2

120−1

+2

120−2

+....+2

120−15

=(−1)(2

120

)(1+

2

1

+

2

2

1

+....+

2

15

1

)

⇓

This is in G.P. whose sum=

2

1

1−(

2

1

)

16

=(−1)(2

120

)×2×(1−(

2

1

)

16

)

=2

105

−2

121

hope this answer heps you

pls mar me as a brainliest

Answer 2

$the \: product \: of \: the \\ \: sum \: given \: in \: above \\ answer$