Question

Pls answer the fifth question step by step asap.

Answer 1

Solution:-
given:-
$y = x + {x}^{2} + \frac{1}{x} + \frac{1}{ {x}^{3} } \\ diff \: with \: r \: t \: x \\ \frac{dy}{dx} = \frac{d}{dx}( x + {x}^{2} + \frac{1}{x} + \frac{1}{ {x}^{3} }) \\ \frac{dy}{dx} = 1 + 2x - {x}^{ - 2} - 3 {x}^{ - 4} \\ \frac{dy}{dx} = 1 + 2x - \frac{1}{ {x}^{2} } - \frac{3}{ {x}^{4} }$