pls answer the following and take 100 pnts free
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so all the possibilities of having childs =b,b g,g
g,b b,g
so the probability =3/4
g,b b,g
so the probability =3/4
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childrens (sample space) = { (boy, boy), (boy, girl), (girl, boy), (girl, girl)}
n( atleast one girl) = 3
P ( atleast one girl) = 3/4
n( atleast one girl) = 3
P ( atleast one girl) = 3/4
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