Math, asked by anjaligodara2003, 1 year ago

Pls answer the following question!!

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Answered by stark17A

Answer for Q3
as we know
1. Angle PBA = 30°.
2. Assume the line from point P to O
then the triangle POB in which angle OBP is 30 and the line from P to O creates 90° on bothsides and in triangle POB this 90° is
divided and the angle OPB is 45° therefore angle POB is 105°.
3. so, the angle OPA is 45° therefore in triangle APB the angle APB is 90°
4. Now we see the triangle PTB where angle PBT = 30° and TPB is now 45° + 45° 45° = 135°
therefore tthe angle PTB = 15°

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stark17A: because there is 90° on both side from tangent to midpoint of circle

anjaligodara2003: But how can we say that it will be 45°

stark17A: because 90° is divided by angle OPB

stark17A: i also sent you an image of this question

anjaligodara2003: But it's not given in the qstn that OPB divides 90°

stark17A: well, if everything was given in question than why we work for solution

stark17A: but, i said we have to assume it that OPB is 45° ,as the the line OP is not directly matching to the midpoint of the diameter,maybe OPB is 30° then APO is 60° because thei total is 90°

stark17A: i maybe wrong, if you think but i suggest you to check the key in this book is the angle PTA is 15°

anjaligodara2003: Okk leave it

stark17A: but is the answer 15° because i'm might be wrong

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