Question

pls answer the following questions fast
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Answer 1

Step-by-step explanation:

I hope its help you out okkk

Answer 2

$\huge\frak{\underbrace{\red{Solution (a) :}}}$

$\implies{\bf{ \dfrac{ (216)^{\frac{-2}{3}} \times (32)^{\frac{1}{5}}}{9^{\frac{-3}{2}} \times 7^{0}}}}$

• Here, we have to simplify this.

$\implies{\sf{ \dfrac{ (6)^{3\times \frac{-2}{3}} \times (2)^{5 \times \frac{1}{5}}}{3^{2\times \frac{-3}{2}} \times 1}}}$

$\implies{\sf{ \dfrac{ (6)^{-2} \times (2)^{1}}{3^{-3}}}}$

$\implies{\sf{ \dfrac{ (3\times 2)^{-2} \times (2)^{1}}{3^{-3}}}}$

$\implies{\sf{ \dfrac{ (3)^{-2} \times (2)^{-2} \times (2)^{1}}{3^{-3}}}}$

$\implies{\sf{ \dfrac{ (3)^{-2} \times (2)^{-2+1}}{3^{-3}}}}$

$\implies{\sf{ \dfrac{ (3)^{-2} \times (2)^{-1}}{3^{-3}}}}$

$\implies{\sf{\dfrac{ \frac{1}{3^{2}} \times \frac{1}{2}}{ \frac{1}{3^{3}}}}}$

$\implies{\sf{\dfrac{ \frac{1}{9} \times \frac{1}{2}}{ \frac{1}{27}}}}$

$\implies{\sf{\dfrac{ \frac{1}{18}}{ \frac{1}{27}}}}$

$\implies{\sf{ \dfrac{1}{18} \times \dfrac{27}{1}}}$

$\large\implies{\boxed{\bf{\orange{ \dfrac{2}{3}}}}}$

$\huge\frak{\underbrace{\red{Solution (b) :}}}$

$\implies{\sf{ (3)^{2x} \times (3)^{3x} = (3)^{20}}}$

$\implies{\sf{ (3)^{2x+3x} = (3)^{20}}}$

$\implies{\sf{ (3)^{5x} = (3)^{20}}}$

• If bases are equal then exponents will also be equal.

$\implies{\sf{ 5x=20}}$

$\large\implies{\boxed{\bf{\orange{ x= 4}}}}$