Question

pls answer the Q... please.....

Answer 1

it is given that <B is 90
&
<BAC = 28
So,
<A+<B+<C =180 (because the sum of all triangles is 180)
28+90+<C=180
118+<C=180
<C=180-118
<C= 62

Answer 2

Hoi!..

In ∆ABC, B = 90°, A= 28° & C = ?

Now,
we know that,

A+B+C=180° $\textbf{(angle sum property)}$

therefore,

28°+90°+C = 180°
=> C = 180°-28°-90°
=> C = 180° - 118°
$\textbf{=> C = 62° }$

Thank u!!!...☺️