Question

Pls answer the question....

Answer 1

Step-by-step explanation:

81^(1/4) = 3

216^(1/3) = 6

32^(1/5) = 2

225^(1/2) = 15

3-(8*6)+ (15*2)+ 15 = 3-48+30+15 = 0

Answer 2

Answer:

$\sqrt[4]{81} - 8 \times \sqrt[3]{216} + 15 \times \sqrt[5]{32} + \sqrt{225} \\ = (3 {}^{4} ) {}^{ \frac{1}{4} } - 8 \times (6 {}^{3} ) {}^{ \frac{1}{3} } + 15 \times (2 {}^{5} ) {}^{ \frac{1}{5} } + 15 \\ = 3 - 8 \times 6 + 15 \times 2 + 15 \\ = 3 - 48 + 30 + 15 \\ = 0$