pls answer the question
Attachments:
Answers
Answered by
2
Answer:
ΔABC is an isosceles triangle.
∴ AB = AC
⇒ ∠ACB = ∠ABC
[∴ Angles opposite to equal sides are equal]
Now, in ΔBEC and ΔCFB, we have
∠EBC = ∠FCB
[Proved]
BC = CB
[Common]
and ∠BEC = ∠CFB
[Each = 90°]
∴ ΔBEC ≌ ΔCFB
[Using ASA criteria]
⇒ Their corresponding parts are equal.
i.e. BE = CF
Similar questions
Hindi,
3 months ago
Math,
3 months ago
Physics,
7 months ago
Physics,
7 months ago
Business Studies,
10 months ago
CBSE BOARD X,
10 months ago
Science,
10 months ago