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let base angles be X and y ( where X=y) and vertex angle be z
given: 2(X+y) =z --------1
X+y+z =180
X+y=180 - z--------2
subs 2 in 1
2(180-z)=z
360-2z=z
360=3z
z=360/3
z=120°
subs this in 2
X+y= 180-120
X+y = 60
X+X = 60
2x = 60
X=60/2
X=y= 30°
hence the angles of the isosceles triangle are
120°,30°and 30°
hope it helps
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