Question

pls answer the question ​

Answer 1

a = -2/3

b = 5/6

c = -5/8

equation given - (a+b) + c = a + (b+c) (property of association)

• lets replace variables by constants :

(-2/3+5/6) + -5/8 = -2/3 (5/6+-5/8)

• now let's solve the LHS first:

(-2/3+5/6)

-4/6+5/6

-4+5

6

= 1/6

= 1/6+(-5/8)

= 4/24+(-15/24)

= 4+(-15)

24

= -11/24

• let's solve the RHS now

-2/3+(5/6+-5/8)

-2/3 + (5/6+(-5/8))

-5/8+5/6

-15/24+20/24

-15+20

24

5

24

= -2/3+5/24

= -16/24+5/24

-16+5

24

= -11/24

= -11/24 = -11/24

hence proved

HOPE IT HELPS:)

Answer 2

$(a + b) + c = a + (b + c)$

$After \: adding \: the \: values$

$( \frac{ - 2}{3} + \frac{5}{6}) + \frac{ - 5}{8} = \frac{ - 2}{3} + ( \frac{5}{6} + \frac{ - 5}{8} )$

$LHS$

$lhs \: =( ( \frac{ - 2}{3} \times \frac{2}{2} ) + \frac{5}{6}) + \frac{ - 5}{8}$

$lhs \: = \frac{ (- 4 )+ 5}{6} + \frac{ - 5}{8}$

$lhs \: = \frac{1}{6} + \frac{ - 5}{8}$

$lhs \: = \frac{1}{6} \times \frac{8}{8} + \frac{ - 5}{8} \times \frac{6}{6}$

$lhs \: = \frac{1}{3} \times \frac{4}{8} + \frac{ - 5}{4} \times \frac{3}{6}$

$lhs \: = \frac{4 + ( - 15)}{24}$

$lhs \: = \frac{ - 11}{24}$

$RHS$

$rhs\: = \frac{ - 2}{3} +( \frac{5}{6} \times \frac{8}{8} ) + ( \frac{ - 5}{8} \times \frac{6}{6})$

$rhs \: = \frac{ - 2}{3} + ( \frac{5}{3} \times \frac{4}{8}) + ( \frac{ - 5}{4} \times \frac{3}{6} )$

$rhs \: = \frac{ - 2}{3} + ( \frac{20}{24} + \frac{ - 15}{24} )$

$rhs \: = \frac{ - 2}{3} + \frac{20 + ( - 15)}{24}$

$rhs \: = \frac{ - 2}{3} + \frac{5}{24}$

$rhs \: = ( \frac{ - 2}{3} \times \frac{8}{8}) + \frac{5}{24}$

$rhs \: = \frac{( - 16) + 5}{24}$

$rhs \: = \frac{ - 11}{24}$

$Since, \frac{ - 11}{24} = \frac{-11}{24}$

$\: \: \: \: LHS = RHS$

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