Question

pls answer the question
(3x+4y)(3x-4y) ​

Answer 1

perimeter of triangle = sum of the sides (a+b+c)

Given: one side= 3x+4y metres

(3x+4y) + (3x+4y) + (3x+4y)first solve the first two sets

3x(3x+4y)+4y(3x+4y)

=9x^2 + 12xy + 12xy + 16y^2

= 9x^2 + 24xy + 16y^2 + (3x+4y)

= 9x^2(3x+4y) + 24xy(3x+4y) + 16y^2(3x+4y)

= 27x^3 + 36x^2y + 72x^2y + 96xy^2 + 38xy^2 + 64y^3

= 27x^3 + 108x^y + 134xy^2 + 64y^3

perimeter = 27x^3 + 108x^y + 134xy^2 + 64y^3

Answer 2

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Apply

$(a + b)(a - b) = a {}^{2} - b {}^{2}$

$(3x) {}^{2} - (4y) {}^{2}$

$9x {}^{2} - 16y {}^{2}$

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