Question

Pls answer the question

Answer 1

Answer:

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Answer 2

Answer:

f(1/2)=1/168

f(0)=20/399

Step-by-step explanation:

Let's find f(1/2) first.

Given equation is f(x)+20f(1-x)=$x^3$

let's appply x=1/2

f(1/2)+20f(1-1/2)=$(1/2)^3$

f(1/2)+20f(1/2)=1/8

21f(1/2)=1/8

f(1/2)=1/168.

Now apply x=0

f(0)+20f(1-0)=(0)^3

f(0)+20f(1)=0

f(0)= -20f(1)--(1)

Now apply x=1

f(1)+20f(1-1)=(1)^3

f(1)+20f(0)=1

from (1)

f(1)+20(-20f(1))=1

f(1)-400f(1)=1

-399f(1)=1

f(1)= -1/399--(2)

applying (2) in eq(1) we get

f(0)= -20(-1/399)

f(0)=20/399