Question

pls answer the question​

Answer 1

Answer:

The three consecutive multiples of 11  are 110, 121 and 132.

Step-by-step explanation:

Let the three consecutive multiples of 11  are 11x,  11x + 11  and  11x + 22

Their sum is 363

11x + 11x + 11 + 11x + 22 = 363

11x + 11x + 11x + 11 + 22 = 363

(11 + 11+ 11)x + (11+22) = 363

33x + 33 = 363

33x = 363 −33

33x = 330

x = 330/33

x = 10

First multiple  = 11x = 11×10 =  110

Second multiple  =11x + 11= 110 + 11 = 121

Third multiple  = 11x +22 = 110 + 22 = 132