Question

Pls answer the question....

Answer 1

Given,
Mass=2Kg
time=2sec.
Displacement=x=t³/3
$x = \frac{1 }{3} t ^{3}$
Now,instantaneous Velocity=
$\frac{d}{dt} ( \frac{ {t}^{3} }{3} ) \\ = \frac{3}{3} {t}^{2} \\ = {t}^{2}$
Instantaneous Acceleration=
$\frac{d}{dt} {t}^{2} = 2t$

Now in Acceleration in:
the First sec.=2×1=2
the Second sec. =2×2=4.

So Total Acceleration=2×4=8

So Force=mass×acceleration
→Force=2×8=16J

I think This is How you solve The Question...

Hope it Helps... Thank you...