Question

Pls answer the question

Answer 1

electric flux = E*A*cos(theta), where theta= angle between E vector and Area A vector.

now electric flux=

=10*0.1²*cos180°+{(50*0.1+10)*0.1²*cos0°}

= -(10 * 0.1²) + {(50*0.1+10)* .1²}

= -0.1 + 0.15

= .05

= 5/100

= 1/20

and according to Guass law,

electric flux = q/epsilon

==> 1/20 = q/ epsilon

==> q = epsilon/20.

option (1) q= epsilon/20