Question

pls. answer the question below

Answer 1

0.7142853120334.....

Answer 2

Answer:

⇒ (x + 3y)/(x - 3y)

Step-by-step explanation:

$=>Given:\frac{2x^2+5xy-3y^2}{2x^2-7xy+3y^2}$

$=>\frac{2x^2-xy+6xy-3y^2}{2x^2-xy-6xy+3y^2}$

$=>\frac{x(2x-y)+3y(2x-y)}{x(2x-y)-3y(2x-y)}$

$=>\frac{(x+3y)(2x-y)}{(x-3y)(2x-y)}$

$=>\frac{x+3y}{x-3y}$

Hope it helps!