Question

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Answer 1

Answer:

traingle abc is perpendicular of AE

ab/ae= do/or

then points O is mid point of BC

hence proof

Answer 2

Answer:

Given

BE = AB

AB = CD(Opposite sides of parallelogram are equal)

so BE = CD ( ie. O is the midpoint of BC)

To prove

OB =OC

PROOF

AB = CD (Opposite sides of parallelogram is equal)

In △OBE and △ OCD

BE. = CD ( Given)

∠OBE. = ∠ OCD ( Alternate Interior Angles)

∠ODC = ∠OEB (Alternate Interior Angles)

By ASA Congruency criterion

△OBE ≅ △ OCD

So OB = OC =BC/2 ( By CPCT)

PROVED that O IS THE MID POINT OF BC

HOPE IT IS HELPFUL TO YOU